Loop Law in Physics

Next, we need to select the loops. In Figure 6.3.10, the loop includes the voltage source and resistors and. The loop starts at the point, then passes through the points , , and , and then returns to the point. The second loop, loop, starts at the point and includes the resistors and the voltage source. Kirchhoff`s second rule (the loop rule) applies to potential differences. The loop rule is given in terms of potential energy rather than potential, but the two have since been linked. In a closed circuit, regardless of the energy supplied by a voltage source, energy must be transferred from devices in the loop to other forms, as there is no other way to transfer energy inside or outside the circuit. The Kirchhoff loop rule states that the algebraic sum of potential differences, including the voltage provided by voltage sources and resistors, must be zero in each loop. For example, consider a simple loop without joints, as shown in Figure 6.3.3. Just as a check, we find that indeed [latex]boldsymbol{I_1 = I_2 + I_3}[/latex]. The results could also have been verified by entering all values into the abcdefgha loop equation. Answer: The Kirchhoff loop rule states that the sum of the voltage differences around the loop must be zero.

In order to find the sum, a travel direction must be selected. The direction of the positive current is indicated clockwise, and it is therefore easier to use it as the direction of travel to find the sum. The voltage source or battery on the left side of the figure has a positive voltage value clockwise. The three resistors cause voltage drops in this direction. The amplitude of the voltage drops is equal to the resistance multiplied by the current in the loop. The sum of the voltage differences is: We measure the voltage differences in volts (V). If you have current I in the loop with ampere (A) and resistance of circuit elements in ohms (Ω), we can determine the voltage difference via a resistor with the formula V = IR. 1) The circuit loop in the figure below consists of three resistors and a voltage source (battery).

The current in the loop is I = +4.00 A clockwise. The battery provides a voltage of vb = 100.0 V. The resistance values for two of the three resistances are shown in the figure. What is the value of the resistance R3? (sum V) is the sum of the voltage differences around a circuit loop that is 0 The application of the junction and loop rules gives the following three equations. We have three unknowns, so three equations are needed. 4: Apply the loop rule to the afedcba loop in Figure 7. Now let`s look at the abcdea loop. When we go from a to b, we cross [latex]boldsymbol{R_2}[/latex] in the same (assumed) direction of the current [latex]boldsymbol{I_2}[/latex], and therefore the potential change is [latex]boldsymbol{-I_2R_2}[/latex]. Then, if we go from b to c, we go from – to +, so the potential change is [latex]boldsymbol{+ textbf{emf}_1}[/latex]. If you go through the internal resistance [latex]boldsymbol{r_1}[/latex] from c-to-d, you get [latex]boldsymbol{-I_2r_1}[/latex].

If you complete the loop from d to a again, a resistor is traversed in the same direction as its current, causing the potential of [latex]boldsymbol{-I_1R_1}[/latex] to change. In any “loop” of a closed circuit, there can be any number of circuit elements such as batteries and resistors. The sum of the voltage differences between all these circuit elements must be zero. This is called the Kirchhoff loop rule. Voltage differences are measured in volts (V). If the current I in the loop is specified in amps (A) and the resistance of the circuit elements in ohms (Ω), the voltage difference can be determined via a resistor with the formula. When selecting loops in the circuit, you need enough loops to cover each component once, without repetitive loops. Figure 6.3.7 shows four loop choices for solving an example circuit; Choices (a), (b) and (c) have enough loops to completely detach the circuit. Option (d) reflects more loops than necessary to solve the circuit. When analyzing AC or DC circuits based on Kirchhoff circuit laws, you should be clear with all terminologies and definitions that describe circuit components such as paths, nodes, networks, and loops.

This circuit is so complex that currents cannot be found using Ohm`s law and series-parallel techniques – it is necessary to use Kirchhoff`s rules. Flows have been shown in the figure by , and assumptions have been made about their directions. The positions in the diagram were labeled with letters. In the solution, we apply the junction and loop rules and look for three independent equations that allow us to solve the three unknown currents. Fig. 1: Kirchhoff`s rules can be applied to any circuit because they are applied to circuits of two conservation laws. Conservation laws are the most widely used principles in physics. It is usually mathematically easier to use the rules for series and parallels in simpler circuits, so we emphasize Kirchhoff`s rules for use in more complicated situations. But the rules for series and parallels can be derived from Kirchhoff`s rules. In addition, Kirchhoff`s rules can be extended to devices other than resistors and EMVs such as capacitors and are one of the basic analyzers in circuit analysis.

Kirchhoff`s second rule (the loop rule) is an application of energy conservation. The loop rule is given in terms of potential [latex]boldsymbol{V}[/latex] and not potential energy, but the two are related because [latex]boldsymbol{textbf{PE}_{textbf{elec}} = qV}[/latex]. Remember that EMC is the potential difference of a source when no current flows. In a closed circuit, the energy provided by electromagnetic fields must be transferred from devices in the loop to other forms, as there is no other way to transfer energy inside or outside the circuit. Figure 3 shows the potential changes in a simple series chaining loop. Kirchhoff`s second rule requires [latex]boldsymbol{textbf{emf} – Ir – IR_1 – IR_2 = 0}[/latex]. Rearranged is [latex]boldsymbol{textbf{emf} = Ir + IR_1 + IR_2}[/latex], which means that the CEM is equal to the sum of the [latex]boldsymbol{IR}[/latex] (voltage) in the loop. Finally, we check the loop. We start at the point and move to a point and cross in the opposite direction as the current flows. Potential waste is added. Then we cross and in the same direction as the current flow and subtract the potential drops and.

Note that the current is equal by the resistors and because they are connected in series.